Sorry for my bad english.
I use MathJax, because it gives me perfect font quality (even exporting page as PDF file gives you perfect result). Downside is the low speed of rendering really big posts.How to use
Add this lines to your post (in HTML mode):
Then surround math code by $ if you want inline math:
---> Do wou now formula $E=mc^{2}$?
Or by $$, if you want stand-alone math: $$E=mc^{2}$$
This code gives you inline math:
This code includes color.js extension.
I need colors.js extension, because I use Lyx as the main math editor. By default, MathJax color formula in TeX mode, not LaTeX. Feel different, this code
{\color{blue}x_{1}+\cfrac{a_{12}}{a_{11}}x_{2}+\cfrac{a_{13}}{a_{11}}x_{3}+\cfrac{a_{14}}{a_{11}}x_{4}+...+\cfrac{a_{1n}}{a_{11}}x_{n}=\cfrac{b_{1}}{a_{11}}}
in LaTeX mode (with color.js) looks like:
$${\color{blue}x_{1}+\cfrac{a_{12}}{a_{11}}x_{2}+\cfrac{a_{13}}{a_{11}}x_{3}+\cfrac{a_{14}}{a_{11}}x_{4}+...+\cfrac{a_{1n}}{a_{11}}x_{n}=\cfrac{b_{1}}{a_{11}}}$$
but by default:
$${\color{blue}x}_{1}+\cfrac{a_{12}}{a_{11}}x_{2}+\cfrac{a_{13}}{a_{11}}x_{3}+\cfrac{a_{14}}{a_{11}}x_{4}+...+\cfrac{a_{1n}}{a_{11}}x_{n}=\cfrac{b_{1}}{a_{11}}$$
---> Do wou now formula $E=mc^{2}$?
Or by $$, if you want stand-alone math: $$E=mc^{2}$$
$E=mc^{2}$ - inline
$$E=mc^{2}$$ - stand-alone
That's all. Now you have math in your blog.
Configuration
Without this code math cannot be rendered at all.This code gives you inline math:
This code includes color.js extension.
I need colors.js extension, because I use Lyx as the main math editor. By default, MathJax color formula in TeX mode, not LaTeX. Feel different, this code
{\color{blue}x_{1}+\cfrac{a_{12}}{a_{11}}x_{2}+\cfrac{a_{13}}{a_{11}}x_{3}+\cfrac{a_{14}}{a_{11}}x_{4}+...+\cfrac{a_{1n}}{a_{11}}x_{n}=\cfrac{b_{1}}{a_{11}}}
in LaTeX mode (with color.js) looks like:
$${\color{blue}x_{1}+\cfrac{a_{12}}{a_{11}}x_{2}+\cfrac{a_{13}}{a_{11}}x_{3}+\cfrac{a_{14}}{a_{11}}x_{4}+...+\cfrac{a_{1n}}{a_{11}}x_{n}=\cfrac{b_{1}}{a_{11}}}$$
but by default:
$${\color{blue}x}_{1}+\cfrac{a_{12}}{a_{11}}x_{2}+\cfrac{a_{13}}{a_{11}}x_{3}+\cfrac{a_{14}}{a_{11}}x_{4}+...+\cfrac{a_{1n}}{a_{11}}x_{n}=\cfrac{b_{1}}{a_{11}}$$